Learn-c-by-examples-program-to-search-string-in-c
提供:Dev Guides
Cで文字列を検索するプログラム
実装
今、私たちはプログラムの実際の実装が表示されます-
#include <stdio.h>
#include <string.h>
int main() {
char s1[] = "Beauty is in the eye of the beholder";
char s2[] = "the";
int n = 0;
int m = 0;
int times = 0;
int len = strlen(s2); //contains the length of search string
while(s1[n] != '\0') {
if(s1[n] == s2[m]) { //if first character of search string matches
//keep on searching
while(s1[n] == s2[m] && s1[n] !='\0') {
n++;
m++;
}
//if we sequence of characters matching with the length of searched string
if(m == len && (s1[n] == ' ' || s1[n] == '\0')) {
//BINGO!! we find our search string.
times++;
}
} else { //if first character of search string DOES NOT match
while(s1[n] != ' ') { //Skip to next word
n++;
if(s1[n] == '\0')
break;
}
}
n++;
m=0; //reset the counter to start from first character of the search string.
}
if(times > 0) {
printf("'%s' appears %d time(s)\n", s2, times);
} else {
printf("'%s' does not appear in the sentence.\n", s2);
}
return 0;
}
出力
このプログラムの出力は次のようになります-
'the' appears 2 time(s)