Learn-c-by-examples-display-doubly-linked-list-in-reverse

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実装

このアルゴリズムの実装は以下のとおりです-

#include <stdio.h>
#include <stdlib.h>

struct node {
   int data;
   struct node *prev;
   struct node *next;
};

struct node *head = NULL;
struct node *last = NULL;

struct node *current = NULL;

//display the list
void printList() {
   struct node *ptr = head;

   printf("\n[head] <=>");
  //start from the beginning
   while(ptr != NULL) {
      printf(" %d <=>",ptr->data);
      ptr = ptr->next;
   }

   printf(" [last]\n");
}

//display the list
void print_backward() {
   struct node *ptr = last;

   printf("\n[head] <=>");
  //start from the beginning
   while(ptr != NULL) {
      printf(" %d <=>",ptr->data);
      ptr = ptr->prev;
   }

   printf(" [last]\n");
}

//Create Linked List
void insert(int data) {
  //Allocate memory for new node;
   struct node *link = (struct node*) malloc(sizeof(struct node));

   link->data = data;
   link->prev = NULL;
   link->next = NULL;

  //If head is empty, create new list
   if(head==NULL) {
      head = link;
      return;
   }

   current = head;

  //move to the end of the list
   while(current->next!=NULL)
      current = current->next;

  //Insert link at the end of the list
   current->next = link;
   last = link;
   link->prev = current;
}

int main() {
   insert(10);
   insert(20);
   insert(30);
   insert(1);
   insert(40);
   insert(56);

   printList();
   print_backward();

   return 0;
}

出力

プログラムの出力は次のようになります-

[head] <=> 10 <=> 20 <=> 30 <=> 1 <=> 40 <=> 56 <=> [last]

[head] <=> 56 <=> 40 <=> 1 <=> 30 <=> 20 <=> 10 <=> [last]